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Question
The number of degrees of freedom of a five link plane mechanism with five revolute pairs as shown in the figure is
The number of degrees of freedom of a five link plane mechanism with five revolute pairs as shown in the figure is
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Solution
The correct option is C 2
DOF=3(N−1)−2j−h.
Here, N=5,j=5.(no.of pairs having one degree of freedom)
DOF=3(5−1)−2×5
=12−10=2
DOF=3(N−1)−2j−h.
Here, N=5,j=5.(no.of pairs having one degree of freedom)
DOF=3(5−1)−2×5
=12−10=2
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