The number of diagonals that can be drawn in a (n-3) sided polygon is 1/3 times the number of diagonals that can be drawn in an `n' sided polygon. The value of `n' is -

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Solution

The correct option is A
9

$\frac{(n - 3) (n - 6)}{2}$ = $\frac{n (n - 3)}{2 \times 3}$

$\Rightarrow n = 9$

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The number of diagonals that can be drawn in a (n-3) sided polygon is 1/3 times the number of diagonals that can be drawn in an `n' sided polygon. The value of `n' is -

The correct option is A 9 (n−3)(n−6)2= n(n−3)2×3 ⇒n=9

The correct option is A
9

$\frac{(n - 3) (n - 6)}{2}$ = $\frac{n (n - 3)}{2 \times 3}$

$\Rightarrow n = 9$