Question

Temperature at which the rms speed of O2 is equal to that of neon at 300 K is:

- 280 K
- 680 K
- 180 K
- 480 K

Solution

The correct option is **D** 480 K

Let u1 be the rms speed of O2

u1=√3RT1M1

Let u2 be the rms speed of Ne

u2=√3RT2M2

now,

u1=u2√T1M1=√T2M2

√T132=√30020

T1=480 K

Let u1 be the rms speed of O2

u1=√3RT1M1

Let u2 be the rms speed of Ne

u2=√3RT2M2

now,

u1=u2√T1M1=√T2M2

√T132=√30020

T1=480 K

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