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Question

The number of electron pairs (ep) in ClF3 is
  1. 5

  2. 4

  3. 6

  4. 7


Solution

The correct option is A

5


The formula for electron pairs is

ep = (V+L+AC)2     [V = number of valance electrons of central atom]

                                              [L = number of Ligands]

                                              [A = Anionic charge]

                                              [C = Cationic charge]

In ClF3,

                Central atom is Cl

Valance electrons in chlorine is 7

Number of Ligands = 3

Therefore,         

ep = (7+3+00)2 

ep = 102

ep = 5

The number of electron pairs in ClF3 is 5

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