The number of electrons involved in the reduction of $C r_{2} O_{7}^{2 -}$ in acidic solution to $C r^{3 +}$ is

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Solution

The correct option is C
3

In this reaction three electrons are required for the reduction of $C r_{2} O_{7}^{2 -}$ into $C r^{3 +}$

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Similar questions

The number of electrons involved in the reduction of $C r_{2} O_{7}^{2 -}$ in acidic solution to $C r^{3 +}$ is

The number of electrons required to reduce chromium completely in Cr $_{2}$ O $_{7}$ $^{2 -}$ to Cr $^{3 +}$ in acidic medium, is

C r_{2} O_{7}^{2 -} \to C r^{3 +}

m o l e s

1 m o l e

{C r_{2} O_{7}}^{2 -}

C r^{3 +}

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