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Question

The number of geometrical isomers possible for the compound are:

$$CH_{3}-CH=CH-CH=CH-C_{2}H_{5}$$ 


A
2
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B
3
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C
4
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D
5
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Solution

The correct option is A 4
In $$CH_3-CH=CH-CH=CH-C_2H_5$$, the number of double bonds is equal to 2. 

Therefore, the number of geometrical isomers $$=2^2$$$$=4$$.

So, the correct option is $$C$$

Chemistry

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