Question

# The number of geometrical isomers possible for the compound are:$$CH_{3}-CH=CH-CH=CH-C_{2}H_{5}$$

A
2
B
3
C
4
D
5

Solution

## The correct option is A 4In $$CH_3-CH=CH-CH=CH-C_2H_5$$, the number of double bonds is equal to 2. Therefore, the number of geometrical isomers $$=2^2$$$$=4$$.So, the correct option is $$C$$Chemistry

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