Question

The number of integral value(s) of $x$ satisfying the inequality ${\tan }^2\left({\sin }^{-1}x\right)>1$ is

Answer 1

Given : ${\tan }^2\left({\sin }^{-1}x\right)>1$
We know that $x\in (-1,1)$
In this interval, substituting the only integer, (i.e $x=0$),
It does not satisfy the inequality.
Hence no integral solution is possible.