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Question

The number of integral values of x for which f(x)=2x220x+42 is negative is 


Solution

f(x)=2x220x+42
Now, 
f(x)=02x220x+42=0x210x+21=0(x3)(x7)=0x=3,7

The graph of the f(x) is 


Therefore f(x) is negative for x(3,7)
Hence, the number of integral value is 3.

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