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Question

The number of ions given by $$[Pt(NH_3)_6]Cl_4$$ in aqueous solution will be:


A
two
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B
three
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C
five
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D
eleven.
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Solution

The correct option is C five
$$[Pt(NH_3)_6]Cl_4 \, \rightleftharpoons \, [Pt(NH_3)_6]^{4+} \, + \, 4Cl^-$$
Total number of ions given ( by dissociation of one molecule of $$[Pt(NH_3)_6]Cl_4$$ in aqueous solution) $$ =$$ 5. This includes one $$ [Pt(NH_3)_6]^{4+}$$ ion and four $$Cl^-$$ ions.

Chemistry

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