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Question

The number of lone pairs of electrons on the central atoms of $$H_2O, \,SnCl_2, \,PCl_3$$ and $$XeF_2$$ respectively are :


A
2, 1, 1, 3
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B
2, 2, 1, 3
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C
3, 1, 1, 2
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D
2, 1, 2, 3
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Solution

The correct option is A 2, 1, 1, 3
The number of lone pairs of electrons on the central atoms of $$\displaystyle H_2O $$, $$\displaystyle SnCl_2 $$, $$\displaystyle PCl_3 $$ and  $$\displaystyle XeF_2$$ respectively , are 2, 1, 1, 3.
$$\displaystyle H_2O $$ has 2 bond pairs and 2 lone pairs of electrons. It has bent geometry.
$$\displaystyle SnCl_2 $$ has 2 bond pairs and one lone pair of electrons. It has bent geometry.
$$\displaystyle PCl_3 $$ has 3 bond pairs and one lone pair of electrons.  It has pyramidal geometry.
$$\displaystyle XeF_2$$ has 2 bond pairs and 3 lone pairs of electrons. It has see-saw shape.
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Chemistry

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