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Question

The number of moles of Br2 produced when two moles of potassium permanganate are treated with excess potassium bromide in aqueous acid medium is:

A
5
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B
3
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C
2
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D
4
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Solution

The correct option is A 5
When 2 moles of KMnO4 reacts with excess of KBr,

2KMnO4+16H++10KBr2Mn2++12K++8H2O+5Br2

5 moles of Br is formed.

Hence, option A is correct.

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