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Limiting Reagent or Reactant

The number of...

Question

The number of moles of $F e_{2} O_{3}$ formed when $0.5 m o l e s$ of $O_{2}$ and $0.5 m o l e s$ of $F e$ are allowed to react are

0.25

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0.5

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1/3

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0.125

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Solution

The correct option is A
0.25

$4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$

limiting reagent is $F e$

$4 m o l e F e \to 2 m o l e F e_{2} O_{3}$

$0.5 m o l e F e \to x m o l e F e_{2} O_{3}$

$x = \frac{0.5 \times 2}{4} = 0.25$

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The number of moles of Fe2O3 formed when 0.5 moles of O2 and 0.5 moles of Fe are allowed to react are

The correct option is A 0.25 4 Fe + 3O2 → 2Fe2O3 limiting reagent is Fe 4 mole Fe → 2 mole Fe2O3 0.5 mole Fe → x mole Fe2O3 x = 0.5 × 24 = 0.25

The number of moles of $F e_{2} O_{3}$ formed when $0.5 m o l e s$ of $O_{2}$ and $0.5 m o l e s$ of $F e$ are allowed to react are

The correct option is A
0.25

$4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$

limiting reagent is $F e$

$4 m o l e F e \to 2 m o l e F e_{2} O_{3}$

$0.5 m o l e F e \to x m o l e F e_{2} O_{3}$

$x = \frac{0.5 \times 2}{4} = 0.25$