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Question

The number of moles of $$H_{2}O_{2}$$ needed to reduce $$1$$ mole of $$KMnO_{4}$$ in acidic medium are:


A
2 moles
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B
2.5 moles
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C
5 moles
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D
3 moles
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Solution

The correct option is D $$2.5$$ moles
The overall reaction is, $$ 6H^+ + 2MnO_4^- + 5H_2O_2 \rightarrow 5O_2 + 2Mn^{2+} + 8H_2O$$.

Therefore, the valency factor of $$H_2O_2 $$ is $$2$$. Since, the valency factor of $$KMnO_4$$ is $$5$$ in acidic medium, the number of moles required to reduce is $$\dfrac{5}{2}$$ moles.
Option B is correct.

Chemistry

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