CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The number of moles of $$KMnO_{4}$$ that will be needed to react with one mole of ferrous oxalate in acidic solution is ?


A
0.4
loader
B
0.6
loader
C
0.8
loader
D
0.1
loader

Solution

The correct option is B $$0.6$$

1)$$0.6$$

2)$$KMnO_4$$ oxidises both ferrous ions to ferric ions and oxalate ions to carbon dioxide as we can see that the oxidation number of$$ C$$ atom in oxalate ion(upper pic)is $$+3$$,while the oxidation state of $$C $$atom in carbon dioxide is $$+4$$(lower pic).

3)So, one mole of oxalate ions loose$$ 2 $$electrons(one electron for each$$ C$$ atom)while one the other hand one mole of ferrous ion looses$$ 1$$ electron so one mole of ferrous oxalate molecule looses $$3 $$electrons in  total so the required number of$$ KMnO_4 $$should provide those $$3 $$electrons as in acidic medium $$KMnO_4$$ gets reduced to $$Mn_2^+$$ ions so one mole of$$ KMnO_4$$ gains$$ 5$$ electrons

4)Hence,$$3/5 ie-0.6$$ mole of$$ KMnO_4 $$is needed to react completely(oxidise completely) one mole of ferrous oxalate.



Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image