Question

The number of non-negtive integer(s) which lie in between the maximum and minimum value of $x$ if $-5\le 2x-4\le -1$ is

• A. $1$
• B. $0$
• C. $2$
• D. $3$

Answer 1

The correct option is C $2$

Given,
$-5\le 2x-4\le -1\Rightarrow -5+4\le 2x-4+4\le -1+4\Rightarrow -1\le 2x\le 3\Rightarrow -\frac{1}{2}\le x\le \frac{3}{2}$

So, $x_{min}=-\frac{1}{2}$ and $x_{max}=\frac{3}{2}$
$\therefore$ Integers which lie in between the maximum and minimum value of $x$ is $0,1.$