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Question

The number of octahedral voids per lattice site in a FCC lattice is

(Rounded off to the nearest integer)


A
1.0
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B
1
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C
1.00
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Solution

In FCC,

No of lattice sites = 6 face centre + 8 corner = 14

No. of octahedral voids = 13

Ratio = 13/14 = 0.92857 = 1 (nearest integer)


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