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Question

The number of permutations of n distinct objects taken r together in which include 3 particular things must occur together

A
n3Cr3(r2)!×3!
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B
nCr3×3!
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C
n3pr3×3!
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D
P3×n3Pr3
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Solution

The correct option is B n3Cr3(r2)!×3!
Number of ways of selection of (r-3) objects out of (n-3) objects
=n3Cr3
When we bundle 3 things together,
no.ofobjects=(r3)+1
=(r2)
which can be arranged in (r-2)! ways also 3 objects
in the bundle can be arranged among themselves in 3! ways
Permutation=n3Cr3(r2)!3!

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