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Question

The number of photons falling per second on a completely darkened plate to produce a force of $$6.62\times 10^{-5}$$N is 'n'. If the wavelength of the light falling is $$5\times 10^{-7}$$m, then $$n=$$______$$\times 10^{22}$$. $$(h=6.62\times 10^{-34}J-s)$$


A
1
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B
5
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C
0.2
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D
3.3
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Solution

The correct option is B $$5$$
$$P=\dfrac{n}{t}.\dfrac{hc}{\lambda}$$
$$Fc=\dfrac{n}{t}.\dfrac{hc}{\lambda}$$
$$\dfrac{n}{t}=\dfrac{f\lambda}{n}$$
$$\dfrac{n}{t}=\dfrac{6.62\times10^{-5}\times5\times10^{-7}}{6.62\times10^{-34}}$$
$$=5\times10^22V$$

Physics
NCERT
Standard XII

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