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Question

The number of positive integral pairs (x,y) satisfying the equation x2y2=3370 is

A
0.0
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B
1
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C
2
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D
4
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Solution

The correct option is A 0.0
3370=2×5×337
So 3370 has only one even factor.
x2y2=3370(xy)(x+y)=3370
the factors of x2y2=(xy)(x+y) would be an even number and an odd number which won't be possible for 2 integrals values of x and y.

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