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Question

The number of real roots of the equation esin xesin x4=0 are


A

1

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B

2

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C

Infinite

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D

0

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Solution

The correct option is D

0


Given equation esin xesin x4=0

Let esin x=y, then given equation can be written as

y24y1=0y=2±5

But the value of y=esin x is always positive, so

y=2+5 (∵ 2 < 5

logey=loge(2+5) ⇒ sin x = loge(2+5)>1

no solution


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