Question

The number of revolutions done by an electron ‘$e$’ in one second in the first orbit of hydrogen atom is

• A. $6.57\times {10}^{15}$
• B. $6.57\times {10}^{13}$
• C. $1000$
• D. $6.57\times {10}^{14}$

Answer 1

The correct option is A $6.57\times {10}^{15}$

Velocity of electron $=2.18\times {10}^6\left(\frac{z}{n}\right)$
Radius of electron $=0.0529\times {10}^{-9}m$
Number of revolution $=\frac{v}{2\pi x}$ rev/sec $T=\frac{2\pi n}{v}$

$=\frac{2.18\times {10}^6\times {10}^9}{2\pi \times 0.0529}rev/sec$
$=6.558\times {10}^{15}rev/sec$

$=6.57\times {10}^{15}rev/sec$