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Question

The number of solution(s) of the equation esinxesinx=4, (e2.72) is

A
0
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B
1
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C
2
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D
4
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Solution

The correct option is A 0
esinx1esinx=4
(esinx)24esinx+4=5(esinx)24esinx1=0esinx=4±202esinx=2±5

Now, sinx[1,1]
esinx[e1,e1]
But 2±5[e1,e1]

Hence, the given equation has no solution.

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