Question

The number of solution(s) of $|y|=(x-1)$ and $|y|=e^{x-2}$ is

• A. $0$
• B. $2$
• C. $4$
• D. $1$

Answer 1

The correct option is B $2$

​We know here, $|y|=(x-1)$ exists only when $(x-1)$ is positive;
$\therefore$ We will be neglecting negative values and the graph will be reflected about $x$ -axis.
Similarly for $|y|=e^{x-2},$ curve can be drawn as mentioned in diagram,



Clearly, there are two intersection points and hence, number of solutions is $2$