The number of stereoisomers possible for a compound of the molecular formula CH₃—CH=CH—(CHCl)—Me is:

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Solution

The correct option is B
4

The molecule has an asymmetric carbon atom and therefore gives a pair of enantiomers. Further due to the presence of the double bond it forms two geometrical isomers.

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The number of stereoisomers possible for a compound of the molecular formula CH₃—CH=CH—(CHCl)—Me is:

C H_{3} - C H = C H - C H (O H) - M e

C H_{3} - C H = C H - C H_{3}

C l - C H = C H - C H (C l) - C H = C H - C l

C H_{3} - C H = C H - C | B r H - C H_{3}

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