The number of stereoisomers possible for $[C o (o x)_{2} (B r) (N H_{3})]^{2 -}$ is____.
[ox = oxalate]

Open in App

Solution

The possible stereoisomers of the $[C o (o x)_{2} (B r) (N H_{3})]^{2 -}$ complex is given below.
The isomers with no plane of symmetry or centre of symmetry is optically active. Hence, it will have a non-superimposable mirror image.
Isomer at the bottom has plane of symmetry hence it is a meso form.

Total stereoisomer = 2 (O.A) (pair of enantiomers) + 1 meso = 3

Suggest Corrections

Similar questions

[P d (N H_{2} - C H (C H_{3}) - C O_{2}^{-})_{2}]^{0}

[P d (N H_{2} - C H (C H_{3}) - C O_{2}^{-})_{2}]

H_{3} C - C H (O H) - C H (O H) - C H_{3}

[I V P d (N H_{3})_{2} (H_{2} O)_{2} B r_{2}]^{2 +}