The number of stereoisomers possible for the following compound is
$C H_{3} - CH = C (OH) - C H_{3} ?$

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Solution

The number of stereo-isomers formed are 4.

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Similar questions

C H_{3} - C H = C H - C H (O H) - C H_{3}

C H_{3} C H_{2} C H_{2} CHO, C H_{3} C H_{2} C H_{2} CH_{2} OH, C_{2} H_{5} O C_{2} H_{5}, C H_{3} C H_{2} C H_{2} C H_{3}

C H_{3} - C H = C H - C H (O H) - M e

The number of stereoisomers possible for a compound of the molecular formula CH₃—CH=CH—(CHCl)—Me is:

C H_{3} - C H = C H - C H_{3}

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