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Question

The number of tangents that can be drawn from the point $$(8,6)$$ to the circle $$x^{2}+y^{2}-100=0$$ is


A
0
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B
1
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C
2
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D
None
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Solution

The correct option is A $$0$$
Given point $$(8,6)$$
$$x^2+y^2-100=0$$
Substitute the value in the equation
$$8^2+6^2-100=100-100=0$$
This means that the point is on the circumference so that only one tangent can be drawn from that point.

Maths

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