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Question
The number of triangles that can be formed by 5 points in a line and 3 points on a parallel line is
The number of triangles that can be formed by 5 points in a line and 3 points on a parallel line is
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Solution
The correct option is C 8C3-5C3-1
The required number of ways = 8C3−5C3−3C3
{Since total points are 8, but 5 are collinear and other three are also collinear}
8C3-5C3-1
The required number of ways = 8C3−5C3−3C3
{Since total points are 8, but 5 are collinear and other three are also collinear}