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Question

The number of ways a pack of 52 cards can be divided among four players in 4 sets, three of them having 17 cards each and the fourth one just 1card is


A
52!(17!)3
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B
52!3.(17!)3
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C
52!3!(17!)3
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D
52!3!3(17!)
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Solution

The correct option is A $$ \dfrac {52!}{(17!)^3} $$
Required number of ways $$=^{52}C_{17}\times ^{35}C_{17}\times
^{18}C_{17}\times ^1C_1 = \cfrac {52!}{(17!)^3} $$
Since persons are distinguishable 

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