The number of ways in which 4 students can sit in 7 chairs in row if there is no empty chair between any two students is

24

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28

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72

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96

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Solution

The correct option is D $96$
Total chairs $= 7$
To select $4$ conservative chairs,
No. of ways $= 7 - 4 + 1$
$(n - r + 1)$
$= 4$
To arrange $4$ students at these $4$ chairs
No. of ways $= 4!$
$\Rightarrow$ Total No. of arrangements $= 4 \times 4!$

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The number of ways in which 4 students can sit in 7 chairs in row if there is no empty chair between any two students is

The correct option is D 96Total chairs =7To select 4 conservative chairs, No. of ways =7−4+1 (n−r+1) =4To arrange 4 students at these 4 chairs No. of ways =4!⇒ Total No. of arrangements =4×4!

The correct option is D $96$
Total chairs $= 7$
To select $4$ conservative chairs,
No. of ways $= 7 - 4 + 1$
$(n - r + 1)$
$= 4$
To arrange $4$ students at these $4$ chairs
No. of ways $= 4!$
$\Rightarrow$ Total No. of arrangements $= 4 \times 4!$