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Question

The number of ways in which $$52$$ cards can be divided into $$4$$ sets of $$13$$ each is


A
52!(13!)4
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B
52!4!(13!)4
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C
52!413
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D
52!13!413
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Solution

The correct option is B $$\displaystyle \frac{52!}{4!(13!)^4}$$
Total number of cards $$=4\times 13=52$$
Assuming all the cards are of different type.
Required number of ways is $$=\cfrac{52!}{13!.13!.13!.13!.4!}=\cfrac{52!}{(13!)^4 4!}$$

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