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Question

The number of ways of distriuting 8 identical balls in 3 distinct boxes so that none of the boxes is empty is
  1. 5
  2. 21
  3. 38
  4. 8C3


Solution

The correct option is B 21
Put one ball in each box first. Remaining 5 identical balls can be distributes in 3 boxes in 7C2
which is equal to 21

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