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Question

The number ot telephone calls received at an exchange per interval for 250 successive one-minute intervals are given in the following frequency table:
No. of calls (x) : 0 1 2 3 4 5 6
No. of intervals (f) : 15 24 19 46 54 43 39
Compute the mean number of calls per interval.

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Solution

Mean = fraction numerator begin display style stack sum f subscript i x subscript i with i equals 1 below end style over denominator N end fraction = fraction numerator 0 cross times 15 thin space plus space 1 cross times 24 plus 2 cross times 19 plus 3 cross times 46 plus 4 cross times 54 plus 5 cross times 43 plus 6 cross times 39 over denominator 15 plus 24 plus 19 plus 46 plus 54 plus 43 plus 39 end fraction

Mean = 865 over 240 equals 3.604

The mean number of calls per interval is 3.604


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