CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The numbers of sides of two regular sides of two regular polygons are in the ratio 4: 5 and their interior angles are in the ratio 15: 16, find the difference in the number of sides of the polygons.


A

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

2


Let the number of sided in polygon A and B be x and y respectively.

As per question, ratio of their side is 4: 5

So, x: y = 4: 5

5x=4y(i)

Ratio of their interior angle is 15: 16.

Interior angle of polygon A={2(x2)x}×90

Interior angle of polygon B={2(y2)y}×90°

{2(x2)x}×90{2(y2)y}×90=15:16

16 yx32y=15xy30x yx=32y30x yx=32y24y(from eq.(i)) yx=8y x=8So, y=10Hence, difference in the side=(108)=2


flag
Suggest Corrections
thumbs-up
8
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Quadrilaterals
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon