CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The numbers of sides of two regular sides of two regular polygons are in the ratio 2: 1 and their interior angles are in the ratio 4: 3, find the sum of the number of sides of the polygons.


A

10

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

15

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

18

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

15


Let the number of sided in polygon A and B be x and y respectively.

As per question, ratio of their side is 1: 2

So, x : y = 1: 2

x = 2y ------- (i)

The ratio of their interior angle is 4: 3.

Interior angle of polygon A = 2(x2x)×90

Interior angle of polygon B = 2(y2y)×90

(2(x2x)×90)(2(y2y)×90) = 43

(x2)y(y2)x = 43

3 yx – 6y = 4xy – 8x

Substitute the value of x from(i)

6y2​ - 6y = 8y2​ -16y

⇒ 2y2​ = 10y

⇒ y = 5

x = 2y = 10

Hence, sum of the sides of polygons = 10 + 5 = 15.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Quadrilaterals
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon