Question

The object is placed at the centre of curvature of a concave mirror of radius $10m$. The image is formed at .

• A. + 5 m
• B. - 5 m
• C. +10 m
• D. -10 m

Answer 1

The correct option is D -10 m

$\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$
$u=-10,f=-\frac{R}{2}=-5$
By substituting these values, $v=-10$.