The object travels 16m in 4s and then another 16m in 2s. What is the average speed of the object?

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Solution

Step 1: Given data
Distance traveled( $d_{1}$ ) = 16 m, Time taken( $t_{1}$ ) = 4 sec
Distance traveled( $d_{2}$ ) = 16 m, Time taken( $t_{2}$ ) = 2 sec
Let $v_{a v g}$ be average speed.
Step 2: Formula used
$v_{a v g} = \frac{T o t a l D i s t a n c e}{T o t a l t i m e}$
Step 3: Finding average speed
Total distance(D), $(d_{1} + d_{2}) = 16 m + 16 m = 32 m$
Total time(T)= $(t_{1} + t_{2}) = 4 s + 2 s = 6 s$
$v_{a v g} = \frac{T o t a l D i s t a n c e}{T o t a l t i m e} = \frac{32 m}{6 s} = 5.33 \frac{m}{s}$ .
Hence, the average speed of the object is $5.33 m / s$ .

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