The only cations present in a slightly acidic solution are $F e^{3 +}, Z n^{2 +} a n d C u^{2 +}$ . The reagent, added in excess to this solution, that would identify and separate $F e^{3 +}$ in one step is:

The only cations present in a slightly acidic solution are $F e^{3 +}, Z n^{2 +}$ and $C u^{2 +}$ . The reagent that when added in excess of this solution would identify and separate $F e^{3 +}$ in one step is:

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The only cations present in a slightly acidic solutions are Fe3+, Zn2+ and Cu2+. The reagent that when added in excess to this solution would identify to separate Fe3+ in one step is

The correct option is B 6 M NH3Fe3+is a third group radical , whose reagent is NH4OH in present of NH4Cl so if 6 M NH3 is added in the slightly acidic (HCl) solution of ions it will lead to the precipitation of Fe3+ as Fe(OH)3. Fe3+(aq)+3NH3(aq)+3H2O→Fe(OH)3↓+3NH+4

The only cations present in a slightly acidic solutions are $F e^{3 +}, Z n^{2 +} and C u^{2 +}$ . The reagent that when added in excess to this solution would identify to separate $F e^{3 +}$ in one step is