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Question

The order and degree of the differential equation sinx(dx+dy)=cosx(dxdy) is

A
order 1, degree 1
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B
order 1, degree 2
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C
order 1, degree not defined
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D
order 1, degree 3
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Solution

The correct option is A order 1, degree 1
Given equation is
sinx(dx+dy)=cosx(dxdy)
sinx dx+sinx dy=cosx dxcosx dy
dx(sinxcosx)=dy(cosxsinx)
dydx=sinxcosxsinx+cosx
Hence, order and degree of the given differential equation is 1,1 respectively.

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