The order and degree of the differential equation y=xdydx+√a2(dydx)2+b2 are
1,2
2,1
1,1
2,2
Given differential equation can be written as y2=x2(dydx)2−2xy.dydx=a2(dydx)2+b2. Hence it is of 1st order and 2nddegree differential equation.