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Chemical Properties of Phenols

The order of ...

Question

The order of reactivity of following alcohols with halogen acids is:

(A) $C H_{3} C H_{2} - C H_{2} - O H$

(B) $C H_{3} - C H_{2} - C | C H_{3} H - O H$

(C) $C H_{3} - C H_{2} - C H_{3} | C | C H_{3} - O H$

(A) > (B) > (C)

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(C) > (B) > (A)

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(B) > (A) > (C)

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(A) > (C) > (B)

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Solution

The correct option is C $(C) > (B) > (A)$
As we know,
stability of carbocations are
$3^{o} > 2^{o} > 1^{o}$
$C H_{3} - C H_{2} - C H_{3} | C^{\oplus} | C H_{3} > C H_{3} - C H_{2} - C H^{\oplus} | C H_{3} > C H_{3} - C H_{2} - C H_{2}^{\oplus}$

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Similar questions

C H_{3} - C | C H_{3} H - C H_{2} - C H_{2} - O H

C H_{3} - O H | C | C H_{3} - C H_{2} - C H_{3}

C H_{3} C H_{3} | C H - O H | C H - C H_{3}

A, B, C

C H_{3} C H_{2} - C H_{2} - O H

C H_{3} C H_{2} - (C H_{3}) C H - O H

C H_{3} C H_{2} - C H_{3} | C | C H_{3} - O H

O H^{-}, N H_{2}^{-}, H C \equiv C^{⊝}

C H_{3} - C H_{2}^{⊝}

300^{\circ} C

(a) C H_{3} - C H_{2} - O H | C H - C H_{3} (b) C H_{3} - 2 - O H | C | C H_{3} - C H_{3}

(c)_{╱ C H_{3}}^{C H_{3} ╲} C H - O H | C | C H_{3} - C H_{3} (d) C H_{3} - O H | C | C H_{3} - C H_{3}

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

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