The order of stability of carbanion is:

1 > 2 > 3

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2 > 3 > 1

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3 > 2 > 1

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none of the above

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Solution

The correct option is A $1 > 2 > 3$

Now the distance between electronegative $O$ atom and negative charge is in order $: 1 < 2 < 3$ . As distance between them increases the stability of carbanion decreases.
Therefore stability of carbanion $: 1 > 2 > 3$ .

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