The orthogonal trajectories for y=Cx2 where C is arbitrary constant represent
A
a family of circles
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a family of straight lines
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a family of ellipses
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
a family of hyperbolas
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C a family of ellipses y=Cx2 ⇒yx2=C, Differentiating x2y′−2xyx4=0 ⇒y′=2yx Replacing dydx by −dxdy, we have y′=−x2y ⇒2ydy+xdx=0 ⇒y2+12x2=constant which represent a family of ellipses.