Question

The oxidation number of carbon is zero in_____________.

• A. HCHO
• B. $C{H}_{2}C{l}_2$
• C. $C_6{H}_{12}{O}_6$
• D. $C_{12}{H}_{22}{O}_{11}$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A HCHO
B $C{H}_{2}C{l}_2$
C $C_{12}{H}_{22}{O}_{11}$
D $C_6{H}_{12}{O}_6$

Oxidation number of $H$ $=+1$

Oxidation number of $Cl$ $=-1$

Oxidation number of $O$ $=-2$

Let oxidation number of $C$ is $x$

1. $HCHO$

$x+2\left(1\right)+(-2)=0$

$x=0$

2.$C{H}_{2}C{l}_2$

$x+2(+1)+2(-1)=0$

$x=0$

3.$C_6{H}_{12}{O}_6$

$x+6(-2)+12(+1)=0$

$x=0$

4.$C_{12}{H}_{22}{O}_{11}$

$12\left(x\right)+22(+1)+11(-2)=0$

$x=0$

Oxidation state of carbon is zero in all compounds.