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Question

The oxidation number of carbon is zero in_____________.


A
HCHO
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B
CH2Cl2
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C
C6H12O6
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D
C12H22O11
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Solution

The correct options are
A HCHO
B $$CH_2Cl_2$$
C $$C_{12}H_{22}O_{11}$$
D $$C_6H_{12}O_6$$
Oxidation number of $$H$$ $$=+1$$
Oxidation number of $$Cl$$ $$=-1$$
Oxidation number of $$O$$ $$=-2$$
Let oxidation number of $$C$$ is $$x$$

1. $$HCHO$$
$$x+2(1)+(-2)=0$$
$$x=0$$

2.$$CH_2Cl_2$$
$$x+2(+1)+2(-1)=0$$
$$x=0$$

3.$$C_6H_{12}O_6$$
$$x+6(-2)+12(+1)=0$$
$$x=0$$

4.$$C_{12}H_{22}O_{11}$$
$$12(x)+22(+1)+11(-2)=0$$
$$x=0$$
Oxidation state of carbon is zero in all compounds.

Chemistry

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