Question

# The oxidation number of carbon is zero in_____________.

A
HCHO
B
CH2Cl2
C
C6H12O6
D
C12H22O11

Solution

## The correct options are A HCHO B $$CH_2Cl_2$$ C $$C_{12}H_{22}O_{11}$$ D $$C_6H_{12}O_6$$Oxidation number of $$H$$ $$=+1$$Oxidation number of $$Cl$$ $$=-1$$Oxidation number of $$O$$ $$=-2$$Let oxidation number of $$C$$ is $$x$$1. $$HCHO$$$$x+2(1)+(-2)=0$$$$x=0$$2.$$CH_2Cl_2$$$$x+2(+1)+2(-1)=0$$$$x=0$$3.$$C_6H_{12}O_6$$$$x+6(-2)+12(+1)=0$$$$x=0$$4.$$C_{12}H_{22}O_{11}$$$$12(x)+22(+1)+11(-2)=0$$$$x=0$$Oxidation state of carbon is zero in all compounds.Chemistry

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