Question

The oxidation number of Ni in $Ni(CO{)}_4$ is $+2$.

• A. True
• B. False
• C. Anomalous
• D. None of these

Answer 1

The correct option is B False

Let $x$ be the oxidation number of $Ni$ in $Ni(CO{)}_4$.
Since the overall
charge on the complex is $0$, the sum of oxidation states of all elements in
it should be equal to $0$.
Therefore, $x+4\left(0\right)=0$
Hence, $x=0$.
Thus, the oxidation number of $Ni$ in $Ni(CO{)}_4$ is $0$.

Hence, the correct option is $\text{B}$