Question

The oxidation number of oxygen in $K_{2}O,K_2{O}_2$ and $K{O}_2$ are respecitvely :

• A. $-2,-1,-\frac{1}{2}$
• B. $-\frac{1}{2},-1,-2$
• C. $-1,-2,-\frac{1}{2}$
• D. $-2,-\frac{1}{2},-1$

Answer 1

The correct option is A $-2,-1,-\frac{1}{2}$

x y z
$K_{2}O,K_2{O}_2,K{O}_2$
$z+x=0z+2y=02z+1=0$
$x=-2y=-1z=-1/2$
Oxidation no. in $K_{2}O$ -2
in $K_2{O}_2$ -1
in $K{O}_2$ -1/2