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Question

The oxidation number of sulphur in H2S2O7 and iron in K4Fe(CN)6 is respectively

A
+ 6 and + 2
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B
+ 2 and + 2
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C
+ 8 and + 2
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D
+ 6 and + 4
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Solution

The correct option is A + 6 and + 2
H2S2O7
2×(+1)+2×x+7×(2)=0
+2+2x14=0
2x=142=12
x=122=+6 for S
K4Fe(CN)6
4×(+1)x+6×(1)=0
4+x6=0
x=64=+2 for Fe.

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