Question

The oxidation state of chromium in $Cr{\left(CO\right)}_6$ is :

• A. $0$
• B. $+2$
• C. $-2$
• D. $+6$

Answer 1

Answer: (A)

$0$

Let $x$ be the oxidation state of $Cr$ in $Cr(CO{)}_6$.
Since, the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore,
$x+6\left(0\right)=0$
or, $x=0$.
Hence, the oxidation state of $Cr$ in $Cr(CO{)}_6$ is $0$.