Question

# The oxidation state of chromium in $$Cr{ \left( CO \right)}_{ 6 }$$ is :

A
0
B
+2
C
2
D
+6

Solution

## The correct option is B $$0$$Let $$x$$ be the oxidation state of $$Cr$$ in $$Cr(CO)_6$$.Since, the overall charge on the complex is $$0$$, the sum of oxidation states of all elements in it should be equal to $$0$$.Therefore,$$x + 6(0) = 0$$or, $$x = 0$$.Hence, the oxidation state of $$Cr$$ in $$Cr(CO)_6$$ is $$0$$.Chemistry

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