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Question

The oxidation state of chromium in $$Cr{ \left( CO \right)}_{ 6 }$$ is :


A
0
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B
+2
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C
2
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D
+6
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Solution

The correct option is B $$0$$
Let $$x$$ be the oxidation state of $$Cr$$ in $$Cr(CO)_6$$.
Since, the overall charge on the complex is $$0$$, the sum of oxidation states of all elements in it should be equal to $$0$$.
Therefore,
$$x + 6(0) = 0$$
or, $$x = 0$$.
Hence, the oxidation state of $$Cr$$ in $$Cr(CO)_6$$ is $$0$$.

Chemistry

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