Question

# The oxidation state of $$Cr$$ in $$K_{2}Cr_{2}O_{7}$$ is:

A
+4
B
+3
C
+6
D
+5

Solution

## The correct option is D $$+6$$$$K_{2}Cr_{2}O_{7}$$Let the oxidation state of $$Cr$$ is $$x$$.$$2(+1) + 2x + 7(-2) = 0$$$$+2 + 2x - 14 = 0$$$$2x - 12 = 0$$$$2x=12$$$$x = +6$$Chemistry

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