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Question

The oxidation state of $$Cr$$ in $$K_{2}Cr_{2}O_{7}$$ is:


A
+4
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B
+3
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C
+6
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D
+5
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Solution

The correct option is D $$+6$$
$$K_{2}Cr_{2}O_{7}$$

Let the oxidation state of $$Cr$$ is $$x$$.

$$2(+1) + 2x + 7(-2) = 0$$

$$+2 + 2x - 14 = 0$$

$$2x - 12 = 0$$

$$2x=12$$

$$x = +6$$

Chemistry

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