Question

# The oxidation state of $$I$$ in $${H_4IO}_6^{-}$$ is :

A
7
B
-1
C
5
D
1

Solution

## The correct option is A 7Let oxidation state of I in $${H_4IO}_6^{-}$$ is $$x$$.Since the overall charge on the complex is $$-1$$, the sum of oxidation states of all elements in it should be equal to $$-1$$.Therefore, $$4+x-12 = -1$$ (Here, oxidation state of H is +1 and oxygen is -2)or, $$x= 7$$Chemistry

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