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Question

The oxidation state of $$I$$ in $${H_4IO}_6^{-}$$ is :


A
7
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B
-1
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C
5
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D
1
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Solution

The correct option is A 7
Let oxidation state of I in $${H_4IO}_6^{-}$$ is $$x$$.
Since the overall charge on the complex is $$-1$$, the sum of oxidation states of all elements in it should be equal to $$-1$$.
Therefore, $$4+x-12 = -1$$ (Here, oxidation state of H is +1 and oxygen is -2)
or, $$  x= 7$$

Chemistry

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