Question

The oxidation state of $I$ in ${H_{4}IO}_6^{-}$ is :

• A. 7
• B. -1
• C. 5
• D. 1

Answer 1

The correct option is A 7

Let oxidation state of I in ${H_{4}IO}_6^{-}$ is $x$.
Since the overall charge on the complex is $-1$, the sum of oxidation states of all elements in it should be equal to $-1$.
Therefore, $4+x-12=-1$ (Here, oxidation state of H is +1 and oxygen is -2)
or, $x=7$